From: dblack@...
Date: 2002-09-29T06:23:10+09:00
Subject: Re: alias versus method_missing

Hi --

On Sun, 29 Sep 2002, Joel VanderWerf wrote:

> Lyle Johnson wrote:
> ...
> > understand why. But I was trying to figure out if there's an alternative
> > that gets me what I really wanted (sort-of a "virtual alias").
>
> It's a little less efficient, but this seems to be virtual:
>
>    class Base
>      def bar; foo; end
>    end
>
> There must be a way to use Class#inherited to good effect, but the
> following doesn't seem to work:
>
>    class Base
>      def self.inherited(sub)
>        sub.class_eval {alias_method :bar, :foo}
>      end
>    end
>
>    Derived.new.bar      # ==> inside Base#foo
>
> However,
>
>    Derived.class_eval {alias_method :bar, :foo}
>    Derived.new.bar      # ==> inside Derived#foo
>
> Anyone understand why? (I'm using 1.6.7, and maybe this would be
> different in a recent 1.7.)

I get two #foo's with 1.6.7.


David

-- 
David Alan Black                      | Register for RubyConf 2002!
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