From: "Berger, Daniel" <djberge@...>
Date: 2002-09-25T05:16:20+09:00
Subject: RE: Regular expression object question

> Hi,
> 
> Well, if your regular expression is not very complicated, you can
> simply use the Regexp "new()" and "source()" methods:
> 
>     re = Regexp.new ('xyz')
>     re = Regexp.new (re.source + 'abc')
>     ....
> 
> Regards,
> 
> Bill

Good idea.  What about overloading += for the source method?

e.g.

re = /xyz/
re.source += "|abc"
puts re.source -> "xyz|abc"

Worth an RFC?

Regards,

Dan


> ==============================================================
> ============
> Daniel Berger <djberge@v55host11.interprise.com> wrote:
> > Hi all,
> 
> > Is there a way to add a new regex to an existing regular expression 
> > object?
> 
> > In other words, say I start with a pattern I want to match:
> 
> > re = /xyz/
> 
> > But later, I decide that I want to also match "abc".  As it 
> stands now, 
> > I have to create a new regex object for that.  Thus:
> 
> > re2 = /abc/
> 
> > This could go on indefinitely, so simply doing this could 
> quickly become 
> > cumbersome:
> 
> > if re.match(string) || re2.match(string)...
> 
> > Thus, what I would like is a way to "push" a new regex onto 
> an old one 
> > (i.e. add an "and" or "or").
> 
> > example:
> 
> > re = /xyz/
> > re.push("|abc") -> re is now /xyz|abc/
> 
> > Thoughts?  Should I just create my own subclass that does 
> this and shut 
> > up?
> 
> > Regards,
> 
> > Dan
> 
> 
> 
> 
> 
>