From: William Djaja Tjokroaminata <billtj@...>
Date: 2002-09-25T02:21:15+09:00
Subject: Re: Regular expression object question

Hi,

Well, if your regular expression is not very complicated, you can
simply use the Regexp "new()" and "source()" methods:

    re = Regexp.new ('xyz')
    re = Regexp.new (re.source + 'abc')
    ....

Regards,

Bill
==========================================================================
Daniel Berger <djberge@v55host11.interprise.com> wrote:
> Hi all,

> Is there a way to add a new regex to an existing regular expression 
> object?

> In other words, say I start with a pattern I want to match:

> re = /xyz/

> But later, I decide that I want to also match "abc".  As it stands now, 
> I have to create a new regex object for that.  Thus:

> re2 = /abc/

> This could go on indefinitely, so simply doing this could quickly become 
> cumbersome:

> if re.match(string) || re2.match(string)...

> Thus, what I would like is a way to "push" a new regex onto an old one 
> (i.e. add an "and" or "or").

> example:

> re = /xyz/
> re.push("|abc") -> re is now /xyz|abc/

> Thoughts?  Should I just create my own subclass that does this and shut 
> up?

> Regards,

> Dan