From: gminick <gminick@...>
Date: 2002-09-24T03:19:26+09:00
Subject: Re: another easy one...

On Tue, Sep 24, 2002 at 02:37:04AM +0900, gminick wrote:
> On Tue, Sep 24, 2002 at 01:09:45AM +0900, Mark Probert wrote:
> > Say, ch is a character and I want to find if it
> > exists in a regexp /A-Za-z0-9_/.  How do I do it?
> Don't know if it is possible to use include? here,
> but you can do this with "=~":
> c =~ /[A-Za-z0-9_]/
> Returns 0 if true, nil if false.
Other way of doing it:

c[/[A-Za-z0-9_]/]

for example:

a = "blah"
if a[/([A-Za-z0-9_])/] # true
   print $1,"\n"
end

if a[/([\!\@\%])/] # false
   print $1,"\n"
end


-- 
[ Wojtek gminick Walczak ][ http://gminick.linuxsecurity.pl/ ]
[ gminick (at) hacker.pl ][ gminick (at) underground.org.pl/ ]