From: William Djaja Tjokroaminata <billtj@...>
Date: 2002-09-24T03:18:26+09:00
Subject: Re: another easy one...

Hi,

As has been pointed out, I think you were mixing string, regular
expression and array.  If you want to use regexp, you can write

    c =~ /[A-Za-z0-9_]/    # will give you the char pos or nil

If you want to use array, you can write

    [('A'..'Z').to_a, ('a'..'z').to_a, (0..9).to_a,
'_'].flatten.include? c    # will give you true or false

And if you want to use string, you wrote it correctly:

    c.count("A-Za-z0-9_")    # will give you the number of occurences

Regards,

Bill
===========================================================================
Mark Probert <probertm@nortelnetworks.com> wrote:

> My brain just isn't working this morn...

> Say, ch is a character and I want to find if it
> exists in a regexp /A-Za-z0-9_/.  How do I do it?

>          irb> c.include?(/A-Za-z0-9_/)
>          "TypeError: cannot convert Regexp into String"

> I can do:

>          irb> c.count("A-Za-z0-9_")
>          1

> And look for a 0 being a non-match.

> Help, please!  :-)



> -mark.