From: "Peña, Botp" <botp@...>
Date: 2002-08-29T11:12:06+09:00
Subject: RE: Newbie converting brain from perl

how about:

date = "28 Aug 2002"

date, day, month, year = /(\d+) (\w+) (\d+)/.match(date)


well..., you could also petition matz to transfer first entry to last ;-)


> -----Original Message-----
> From: William Pietri [mailto:william-news-383910@scissor.com] 
> Sent: Thursday, August 29, 2002 4:31 AM
> To: ruby-talk@ruby-lang.org
> Subject: Newbie converting brain from perl
> 
> 
> 
> Howdy! As a long time Perl, Java, and Objective-C developer, 
> I'm quite taken 
> with Ruby, and I'm busily converting my brain over. But 
> there's a Perl 
> idiom that I'm having trouble translating. In Perl it goes like this:
> 
>     $date = "28 Aug 2002";
>     ($day, $month, $year) = $date =~ /(\d+) (\w+) (\d+)/;
> 
> 
> In Ruby the best I've been able to do is this:
> 
>     date = "28 Aug 2002"
>     day, month, year = /(\d+) (\w+) (\d+)/.match(date)[1..3]
> 
> But that final [1..3] thing seems inelegant, which makes me think I'm 
> barking up the wrong tree. What's the best Ruby-style way to do this?
> 
> 
> Many thanks,
> 
> William
>