From: "Hal E. Fulton" <hal9000@...>
Date: 2002-08-29T06:33:50+09:00
Subject: Re: Newbie converting brain from perl

----- Original Message -----
From: "William Pietri" <william-news-383910@scissor.com>
Newsgroups: comp.lang.ruby
To: "ruby-talk ML" <ruby-talk@ruby-lang.org>
Sent: Wednesday, August 28, 2002 3:31 PM
Subject: Newbie converting brain from perl


>
> Howdy! As a long time Perl, Java, and Objective-C developer, I'm quite
taken
> with Ruby, and I'm busily converting my brain over. But there's a Perl
> idiom that I'm having trouble translating. In Perl it goes like this:
>
>     $date = "28 Aug 2002";
>     ($day, $month, $year) = $date =~ /(\d+) (\w+) (\d+)/;
>
>
> In Ruby the best I've been able to do is this:
>
>     date = "28 Aug 2002"
>     day, month, year = /(\d+) (\w+) (\d+)/.match(date)[1..3]
>
> But that final [1..3] thing seems inelegant, which makes me think I'm
> barking up the wrong tree. What's the best Ruby-style way to do this?

Hmm. It does seem inelegant, but I'm not sure
how to improve on it.

Things like \1 and \2 are only useful in doing substitutions,
I suppose.

One way, if you don't mind (the new) scanf, would be:

  day, month, year = date.scanf("%d %s %d")


HTH,
Hal