From: Joel VanderWerf <vjoel@...>
Date: 2002-08-29T06:24:54+09:00
Subject: Re: Newbie converting brain from perl

William Pietri wrote:
...
> In Ruby the best I've been able to do is this:
> 
>     date = "28 Aug 2002"
>     day, month, year = /(\d+) (\w+) (\d+)/.match(date)[1..3]

How about:

       day, month, year = /(\d+) (\w+) (\d+)/.match(date)[1..-1]

or

    _, day, month, year = /(\d+) (\w+) (\d+)/.match(date).to_a

Still not quite elegant, but at least the 3 isn't hard-coded.

> 
> But that final [1..3] thing seems inelegant, which makes me think I'm 
> barking up the wrong tree. What's the best Ruby-style way to do this?