From: "James F.Hranicky" <jfh@...>
Date: 2002-08-29T06:18:02+09:00
Subject: Re: Newbie converting brain from perl

On Thu, 29 Aug 2002 05:31:23 +0900
"William Pietri" <william-news-383910@scissor.com> wrote:

>     date = "28 Aug 2002"
>     day, month, year = /(\d+) (\w+) (\d+)/.match(date)[1..3]
> 
> But that final [1..3] thing seems inelegant, which makes me think I'm 
> barking up the wrong tree. What's the best Ruby-style way to do this?

In 1.7, you can use String#match as well:

	all, date, month, year = date.match(/\d+) (\w+) (\d+)/)

Jim