From: Lyle Johnson <jlj@...>
Date: 2002-06-04T00:18:11+09:00
Subject: Re: Infinity (?!)

> I would expect that it is valid for two NaN's to equal each other, but
> that because there are many different possible NaN's, they need not
> necessarily equal each other.

I thought that it was part of the *definition* of NaN that it wasn't equal
to any other number, including itself. So (despite Sean's result) I would
expect:

    ruby -ve 'p((0/0.0) == (0/0.0))'

to always return false.