From: Tamara Temple <tamouse.lists@...>
Date: 2013-06-12T10:23:06+09:00
Subject: Re: Loop with range question

Scott H. <lists@ruby-forum.com> wrote:
> i=0
> loop do
>   i+=1
>   next if i== 3..6
>   print "#{i} "
>   break if i==10
> end
> 
> expected => 1 2 7 8 9 10
> actual =>  warning: integer literal in conditional range
> (don’t understand, thought it was telling me it does not work because it
> can’t transform the range on the fly to the actual integers 3,4,5,6)

Clippy sez: "It appears you are trying to use the flip-flop operator."

Flip-flop is a bit odd, but this should work:

i=0
loop do
  i+=1
  next if i==3 .. i==6 # note the range is the comparisons
  print "#{i} "
  break if i==10
end

output:
=======
1 2 7 8 9 10

a (possibly) more idiomatic way to write that would be:

1.upto(10) do |i|
  next if i==3 .. i==6
  print "#{i} "
end

Still another, perhaps more useful:

1.upto(10).select{|i| true unless i==3 .. i==6 }

which just returns the collection, suitable for other uses besides
printing.
		      
Or, just use the #include? on the subranges as others have
suggested.