From: "Scott H." <lists@...>
Date: 2013-06-12T06:10:40+09:00
Subject: Re: Loop with range question

unknown wrote in post #1112056:
> Am 11.06.2013 18:04, schrieb Scott H.:
>> actual =>  1 2 3 4 5 6 7 8 9 10
>> (so I thought by wrapping the range in a “()” it would convert to
>> 3,4,5,6 and then be able to jump over these integers on output)
>> ================
>
> This might help:
>
> 2.0.0-p195 :018 > (3..6).include? 5
>   => true
> 2.0.0-p195 :019 > (3..6).include? 10
>   => false
>
> Note that a Range and an Integer can never be equal.

You state a range can never be equal to an integer. Does that mean
i == <thing here needs to be an integer>
so is that why (3..6) is not working for me?

Would it make any difference that I'm using 1.9.3-p392?

Did i mention I'm new to ruby and programming :)

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