From: sto.mar@...
Date: 2013-06-12T01:27:42+09:00
Subject: Re: Loop with range question

Am 11.06.2013 18:04, schrieb Scott H.:
> ================
> i=0
> loop do
>    i+=1
>    next if i== (3..6)
>    print "#{i} "
>    break if i==10
> end
>
> expected => 1 2 7 8 9 10
> actual =>  1 2 3 4 5 6 7 8 9 10
> (so I thought by wrapping the range in a “()” it would convert to
> 3,4,5,6 and then be able to jump over these integers on output)
> ================

This might help:

2.0.0-p195 :018 > (3..6).include? 5
  => true
2.0.0-p195 :019 > (3..6).include? 10
  => false

Note that a Range and an Integer can never be equal.


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