From: "Scott H." <lists@...>
Date: 2013-06-12T01:04:17+09:00
Subject: Loop with range question

Hi All, working through understanding loops.  Would someone explain why
I cannot use “next if i=3..6” or “next if i=(3..6)”  in code below.
After each I inserted what I thought I should see as a result versus
what I did get returned. - Scott
================
i=0
loop do
 i+=1
  next if i==3
  print "#{i} "
  break if i==10
end

expected => 1 2 4 5 6 7 8 9 10
actual => 1 2 4 5 6 7 8 9 10
(yeah!)
================
i=0
loop do
  i+=1
  next if i== 3..6
  print "#{i} "
  break if i==10
end

expected => 1 2 7 8 9 10
actual =>  warning: integer literal in conditional range
(don’t understand, thought it was telling me it does not work because it
can’t transform the range on the fly to the actual integers 3,4,5,6)
================
i=0
loop do
  i+=1
  next if i== (3..6)
  print "#{i} "
  break if i==10
end

expected => 1 2 7 8 9 10
actual =>  1 2 3 4 5 6 7 8 9 10
(so I thought by wrapping the range in a “()” it would convert to
3,4,5,6 and then be able to jump over these integers on output)
================

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