From: Love U Ruby <lists@...>
Date: 2013-05-21T23:30:28+09:00
Subject: Re: Enum#each issue

Hans Mackowiak wrote in post #1109718:
> def meth
> [1,2,3].each {|e| p yield(e)}
> end
>
> m = to_enum(:meth)
> m.next #=> 1
>

Great example! but when you do `m.next`, how internally enumerator 
works? Just need one clarification.

As I understand the below:

>> [1,2,4].to_enum
=> #<Enumerator: [1, 2, 4]:each>
>> a = [1,2,4].to_enum
=> #<Enumerator: [1, 2, 4]:each>
>> a.next
=> 1

But you enumerate the method `meth`, so when you do `m.next` how things 
worked as output as `1`? need help here.

> m.feed "e"
>
> m.next
> #printed: "e"
> #return => 2
>
>
> as you can see, feed affects the result of yield, BUT the enumerator
> method need to take care with it

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