From: tamouse mailing lists <tamouse.lists@...>
Date: 2013-05-01T02:55:03+09:00
Subject: Re: how to: convert string to DateTime object

On Tue, Apr 30, 2013 at 12:18 PM, Ana Bia <lists@ruby-forum.com> wrote:
> Hi, can someone please show an example of:
>
> -how to convert a string to a DateTime object using
> DateTime.strptime(1.9.3)

Do you need more than this:
http://www.ruby-doc.org/stdlib-1.9.3/libdoc/date/rdoc/DateTime.html#method-c-strptime
?

> -and how to run an each loop to convert multiple strings

Since I don't know your true need, I'll make something up. Suppose you
have a log file, that looks something like this:

DEBUG 2013-04-23T17:27:50-05:00 - "  ESC[1mESC[35mSpree::Preference
Load (5.5ms)ESC[0m  SELECT `spree_preferences`.* FROM
`spree_preferences` WHERE `spree_preferences`.`key` IS NOT NULL AND
`spree_preferences`.`value_type` IS NOT NULL"
DEBUG 2013-04-23T17:27:50-05:00 - "Cache write:
spree/app_configuration/products_per_page"
DEBUG 2013-04-23T17:27:50-05:00  "Dalli::Server#connect 127.0.0.1:11211"
DEBUG 2013-04-23T17:27:50-05:00 - "Cache write:
spree/app_configuration/track_inventory_levels"
DEBUG 2013-04-23T17:27:50-05:00 - "Cache write:
spree/app_configuration/allow_backorder_shipping"
DEBUG 2013-04-23T17:27:50-05:00 - "Cache write:
spree/app_configuration/checkout_zone"
DEBUG 2013-04-23T17:27:50-05:00 - "Cache write:
spree/app_configuration/allow_ssl_in_production"
DEBUG 2013-04-23T17:27:50-05:00 - "Cache write:
spree/app_configuration/default_development.log Connecting to database
specified by database.yml

And you want to extract the time stamps from that and convert them to
DateTime objects. The following might be a way to do that:

IO.foreach("./log/development.log") do |line|
  timestamp = DateTime.strptime(line.split[1]),'%FT%T%z')
end