From: Regis d'Aubarede <lists@...>
Date: 2013-04-15T07:24:19+09:00
Subject: Re: Looking for more elegant solutions.

def mails( n, times ,already=[], accu=[])
  return accu << already  if n > times
  nexts=(1..times).to_a - already-[n]
  nexts.each { |i| mails( n+1, times, already+[i], accu  ) }
  accu
end

p mails(1,4)

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