On Thu, Mar 28, 2013 at 3:05 PM, <sto.mar@web.de> wrote:

Am 28.03.2013 21:48, schrieb John W Higgins:

On Thu, Mar 28, 2013 at 1:17 PM, Phil H. <lists@ruby-forum.com<= /a>
<mailto:lists@ruby-forum.com>> wrote:

=A0 =A0 This one is stumping me because of all the variables needed. Only t= hing
=A0 =A0 taught before this challenge was basic branches and loops. This is = what
=A0 =A0 I have so far.

=A0 =A0 puts 'Leap Year Calculator'
=A0 =A0 puts ' '
=A0 =A0 puts 'Enter the starting year.'
=A0 =A0 starting_year =3D gets.chomp
=A0 =A0 puts 'Enter the ending year.'
=A0 =A0 ending_year =3D gets.chomp

The rest doesn't work at all because if you put something like 2096-210= 4
you would print out 2096, 2100 which is incorrect in two ways

1) 2100 isn't a leap year
2) 2104 should be printed and your second while clause precludes that

You shouldn't be worrying about the starting year as much as you are -<= br> you need to handle every leap year in the same fashion

So lets try something like this

leap_year =3D starting_year + starting_year % 4 #set yourself onto a
possible leap year to start with

does not work:

Absolutely correct - stupid line by me

How= about

sy =3D starting_year.to_i

then either of

leap_= year =3D sy - sy % 4
leap_year =3D leap_year + 4 unless sy =3D=3D leap_y= ear

or a single line overly cute option

leap_year =3D sy - sy % 4 + = 4 * (sy % 4 <=3D> 0) # I can't think of another way to get the si= gnum function in ruby

John