From: Matthew Kerwin <lists@...>
Date: 2013-03-16T15:01:51+09:00
Subject: Re: combine two regular expressions

Ken Paul wrote in post #1101884:
> Hi there,
>
> How to combine the two regular expressions into one?
>
> reg1 = /\w+[_][0-9]+$/
> reg2 = /\w+$/
>
> it seems that match(/\w+\([_][0-9]+\)?$/ does not work, any idea?

A couple of things:

* \( and \) match literal '(' and ')' characters.  In Ruby regex you
  use unescaped parentheses to mark subpatterns/groups, thus:  /a(bc)d/

So:  /\w+([_][0-9]+)?$/

Also:
* [_] doesn't need to be in a character class, /[_]/ matches the same
  as /_/
* there's a special regex metacharacter \d that matches exactly [0-9]

So you could use:
  reg1 = /\w+_\d+$/
  reg2 = /\w+$/
  regX = /\w+(_\d+)?$/

Although that already looks a bit less readable than your way...

Also:
* \w matches underscores and digits as well as letters, so /\w+/ already
  matches /_[0-9]+/  (in other words, reg2 will already match everything
  you intended from the combined pattern)

irb> s = 'hello_world_123'
=> "hello_world"123"
irb> m = s.match /\w+$/
=> #<MatchData "hello_world_123">
irb> m[0]
=> "hello_world_123"

However, assuming you want to explicitly match /_[0-9]+/ at the end
separately, you could use:

irb> m = s.match /\w+?(_\d+)?$/
=> #<MatchData "hello_world_123" 1:"_123">
irb> m[1]
=> "_123"

Note the question mark after \w+? , it makes it un-greedy (i.e. it
doesn't gobble up the entire rest of the string, the way \w+ would).

Or assuming you actually want to match LETTER+ [ "_" NUMBER+ ] you could
use:

irb> m = s.match /[A-Za-z]+(_\d+)?$/
=> #<MatchData "world_123" 1:"_123">

Note how it didn't match "hello_" since that contains non-letters.  Or
various other combinations and permutations.

All this gleaned from http://www.ruby-doc.org/core-1.9.3/Regexp.html (as
well as a couple of decades playing with regular expressions.)

-- 
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