From: "Kumar R." <lists@...>
Date: 2013-03-05T06:58:52+09:00
Subject: How `next` works in ruby with `unless` ?

The `next` statement is used to skip a part of the loop and continue
with the next iteration of the loop. It can be used in combination with
`for` and `while` statements.

I have seen people using next if there is complicated piece of code
after some condition is being evaluated i.e

    next if @state!=:some_state
    # some long complicated code

Now here I have played with the `next` in my `IRB` as below :

    n = 1
    loop do
    n = n + 1
    next unless n == 10
    print "Good"
    break
    end
    # Good=> nil

The above one understood. Nicely clear.

    n = 1
    #=> 1
    loop do
    print "#{n}"
    n = n + 1
    next puts "hi" unless n == 5
    p "good"
    break
    end
    #1hi
    #2hi
    #3hi
    #4"good"
    #=> nil

In the above code, couldn't understand about which order the lines `puts
"hi"` and `unless n == 5` executed. Which executed first?

The below one leads to the `infinite Loop`.

    n = 1
    #=> 1
    loop do
    print "#{n}"
    n = n + 1
    next puts "hi"; 2 + 3 unless n == 5
    p "good"
    break
    end

whereas this one is good:

    n = 1
    #=> 1
    loop do
    print "#{n}"
    n = n + 1
    next puts "hi", 2 + 3 unless n == 5
    p "good"
    break
    end

    #1hi
    #5
    #2hi
    #5
    #3hi
    #5
    #4"good"
    #=> nil

Please help me here to understand - how does this one resolve that
`forever` loop ?

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