From: Peter Hickman <peterhickman386@...>
Date: 2013-03-05T04:02:33+09:00
Subject: Re: Can't get If statement right

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gets will return a string and therefore option will be a string. "if option
== 2" is expecting option to be an integer

A simple fix would be

option = gets.to_i



On 4 March 2013 18:58, Kat VS <lists@ruby-forum.com> wrote:

> mainMenu = "Main Menu:
>
>     Phone Book Application
>     1.) Print Phone Book
>     2.) Add Entry
>     9.) Quit Application
>
>     Please select an option:"
>
> print mainMenu
>
> option = gets
>
> ( if option == 1
>     print "TODO: Print Phone Book"
>     print mainMenu
>     option = gets
>
>      elsif option == 2
>     print "TODO: Add Entry"
>     print mainMenu
>     option = gets
>
>      elsif option == 9
>     print "TODO: Quit Entry, type 'quit' to exit."
>       quit.get
>         ( if quit == "quit"
>           abort("Goodbye.")
>         else
>           mainMenu
>           option = gets
>         end )
>
>      else
>     print "Error, please enter 1, 2, or 9."
>     print mainMenu
>     option = gets
>
>      end )
>
>
>
>
> Every time I run this it just outputs "Error, please enter 1, 2 or 9."
> No matter what number I enter. What am I doing wrong?? Thanks!
>
> --
> Posted via http://www.ruby-forum.com/.
>
>

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<div dir=3D"ltr">gets will return a string and therefore option will be a s=
tring. &quot;if option =3D=3D 2&quot; is expecting option to be an integer<=
div><br></div><div style>A simple fix would be</div><div style><br></div><d=
iv style>
option =3D gets.to_i</div><div style>=A0<br></div></div><div class=3D"gmail=
_extra"><br><br><div class=3D"gmail_quote">On 4 March 2013 18:58, Kat VS <s=
pan dir=3D"ltr">&lt;<a href=3D"mailto:lists@ruby-forum.com" target=3D"_blan=
k">lists@ruby-forum.com</a>&gt;</span> wrote:<br>
<blockquote class=3D"gmail_quote" style=3D"margin:0 0 0 .8ex;border-left:1p=
x #ccc solid;padding-left:1ex">mainMenu =3D &quot;Main Menu:<br>
<br>
=A0 =A0 Phone Book Application<br>
=A0 =A0 1.) Print Phone Book<br>
=A0 =A0 2.) Add Entry<br>
=A0 =A0 9.) Quit Application<br>
<br>
=A0 =A0 Please select an option:&quot;<br>
<br>
print mainMenu<br>
<br>
option =3D gets<br>
<br>
( if option =3D=3D 1<br>
=A0 =A0 print &quot;TODO: Print Phone Book&quot;<br>
=A0 =A0 print mainMenu<br>
=A0 =A0 option =3D gets<br>
<br>
=A0 =A0 =A0elsif option =3D=3D 2<br>
=A0 =A0 print &quot;TODO: Add Entry&quot;<br>
=A0 =A0 print mainMenu<br>
=A0 =A0 option =3D gets<br>
<br>
=A0 =A0 =A0elsif option =3D=3D 9<br>
=A0 =A0 print &quot;TODO: Quit Entry, type &#39;quit&#39; to exit.&quot;<br=
>
=A0 =A0 =A0 quit.get<br>
=A0 =A0 =A0 =A0 ( if quit =3D=3D &quot;quit&quot;<br>
=A0 =A0 =A0 =A0 =A0 abort(&quot;Goodbye.&quot;)<br>
=A0 =A0 =A0 =A0 else<br>
=A0 =A0 =A0 =A0 =A0 mainMenu<br>
=A0 =A0 =A0 =A0 =A0 option =3D gets<br>
=A0 =A0 =A0 =A0 end )<br>
<br>
=A0 =A0 =A0else<br>
=A0 =A0 print &quot;Error, please enter 1, 2, or 9.&quot;<br>
=A0 =A0 print mainMenu<br>
=A0 =A0 option =3D gets<br>
<br>
=A0 =A0 =A0end )<br>
<br>
<br>
<br>
<br>
Every time I run this it just outputs &quot;Error, please enter 1, 2 or 9.&=
quot;<br>
No matter what number I enter. What am I doing wrong?? Thanks!<br>
<span class=3D"HOEnZb"><font color=3D"#888888"><br>
--<br>
Posted via <a href=3D"http://www.ruby-forum.com/" target=3D"_blank">http://=
www.ruby-forum.com/</a>.<br>
<br>
</font></span></blockquote></div><br></div>

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