From: Henry Maddocks <hmaddocks@...>
Date: 2013-03-04T09:30:09+09:00
Subject: Re: Confusion with Ruby's "case/when" block statement


On 4/03/2013, at 11:22 AM, "Kumar R." <lists@ruby-forum.com> wrote:

> 
> Now look at the above. Both return `true`. Does they output `true` on 
> the same logic? I think `NO`. `"abc".===("abc")` is just like simple 
> string literal comparison `"abc" ==("abc")` comparison. But 
> `String.===("abc")` outputs `true` as `"abc"` which is an instance of 
> `String`.
> 
> Now my question is how ruby detects lefthand side operands types and 
> apply the proper rule of comparisons ?

It doesn't detect anything.You are calling the === method on String, you have even written it as such `String.===("abc")`. Each class is free to implement it how ever they want.

This is basic OO

Henry