From: "Kumar R." <lists@...>
Date: 2013-03-04T07:22:21+09:00
Subject: Re: Confusion with Ruby's "case/when" block statement

10.===(10) #=> true
Numeric.===(10) #=> true

Now look at the above. Both return `true`. Does they output `true` on 
the same logic? I think `NO`. `10.===(10)` is just like `10 ==(10)` 
comparison. But `Numeric.===(10)` outputs `true` as class of `10` which 
is subclass of `Numeric`.


"abc".===("abc") #=> true
String.===("abc") #=> true

Now look at the above. Both return `true`. Does they output `true` on 
the same logic? I think `NO`. `"abc".===("abc")` is just like simple 
string literal comparison `"abc" ==("abc")` comparison. But 
`String.===("abc")` outputs `true` as `"abc"` which is an instance of 
`String`.

Now my question is how ruby detects lefthand side operands types and 
apply the proper rule of comparisons ?

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