From: tamouse mailing lists <tamouse.lists@...>
Date: 2013-02-25T00:59:51+09:00
Subject: Re: How should I print only the last combination when using Array#combination(n) ?

On Sun, Feb 24, 2013 at 9:40 AM, Love U Ruby <lists@ruby-forum.com> wrote:
> tamouse mailing lists wrote in post #1098790:
>> On Sun, Feb 24, 2013 at 9:15 AM, Love U Ruby <lists@ruby-forum.com>
>> wrote:
>>>>>
>>>
>>> --
>>> Posted via http://www.ruby-forum.com/.
>>>
>>
>> I have no idea what you're saying there.
>>
>> Other than get the last combination, what is it you actually want to
>> do? What is the application?
>
> Okay! I want to write a one liner which can give me the below output:

I don't see any example output here...

> which is currently I am not able by the below block code with
> combination,as in the below block I couldn't track the,say,when second
> 'arr' is coming just print it,but not the others.:
>
>>> a.combination(2){|arr| print arr.length;print "~~>";print arr ; print "=>" ; p
> arr}
> 2~~>[1, 2]=>[1, 2]
> 2~~>[1, 3]=>[1, 3]
> 2~~>[2, 3]=>[2, 3]
> => [1, 2, 3]
>
> Please let me know if still my need confuses you.

Still don't know what your need is...

If I guessed, is it this?

1.9.3-head :007 > [1,2,3].combination(2).to_a.last.tap{|t| puts
"#{t.length}~~>#{t}=>#{t}" }
2~~>[2, 3]=>[2, 3]

?

Can you describe what you're trying to do from the beginning before
you decided to go down the combination route?

> --
> Posted via http://www.ruby-forum.com/.
>