Re: Confusion with `nil` value being produced by IRB in case of Array#size manipulation.

Have you even tried to read the documentation???
Did you ever read any tutorial or introductory book???

Please stop posting your "experiments". *READ THE DOCS*.

AGAIN: READ. THE. DOCS!!! READ. SOME. BOOK!!!



Am 24.02.2013 10:45, schrieb Love U Ruby:
> enum[int] = obj → obj
> enum[start, length] = obj → obj
> enum[range] = obj → obj
>
> During my reading and understandding with the above I tried something in
> my IRB as below:
>
> a = []
> # => []
> a.size
> # => 0
>
> Humm, understood. As no element I still added.
>
> a[0]
> # => nil
> a[1]
> # => nil
>
> as the array size is `0`, while trying to access the a[1] getting no
> exception - why so? that means index is there or what?
> what logic does help IRB to  show such `nil` values?

READ THE DOCS.

>
> a[1] = 5
> # => 5
> a
> # => [nil, 5]
>
> The above code what should I say - new value addition or substitution of
> 'nil'?

READ THE DOCS.

> a.size
> # => 2
>
> Okay! so now the size is `2`.
>
> Now in the below as the size is `2` thus a[3] is showing `nil`.
> a[3]          <~~~~ point - I
> # => nil
> a.size
> # => 2
>
>
> Now I added `nil` in the same index intentionaly. And the size got
> changed to `3`.

OF COURSE.

> a[3] = nil
> # => nil
> a.size
> # => 3
> a[3]        <~~~~ point - II
> # => nil
>
> What is the difference between the output of a[3] in point- I and point
> -II ?
> Why does both `nil` value being treated differently as mentioned above?
>


-- 
<https://github.com/stomar/>