From: Alex Gutteridge <alexg@...>
Date: 2013-02-22T18:37:39+09:00
Subject: Re: backslash substitution

On 22.02.2013 09:27, Mario Ruiz wrote:
> I found this solution... but i thought that Ruby had a better way:
>
>
> x="xxxxx P jjjjjj\0\1\2\3.4.1\4\5\6\7\8\9"
> m=""
> x.each_byte {|a|
>   puts a
>   if a<32 then
>     m+="/" + a.to_s()
>   else
>     m+=a.chr
>   end
> }
> puts m

Has that really done what you want though?

>> puts m
xxxxx P jjjjjj/0/1/2/3.4.1/4/5/6/789

-- 
Alex Gutteridge