From: Hans Mackowiak <lists@...>
Date: 2013-02-19T16:26:06+09:00
Subject: Re: splat operator and Ruby instance variable assignments

Love U Ruby wrote in post #1097729:
> Now I have tried the below :
>
>
> C:\>irb --simple-prompt
>>>   class Foo
>>>   def initialize(x,y,z)
>>>   @x, @y, @z= x, y,z
>>>   end
>>>   def to_hash
>>>   [@x => @y]
>>>   end
>>>   end
> => nil
>>> foo=Foo.new(10,11,12)
> => #<Foo:0x11f8968 @x=10, @y=11, @z=12>
>>> a,*b=foo
> => #<Foo:0x11f8968 @x=10, @y=11, @z=12>
>>> a
> => #<Foo:0x11f8968 @x=10, @y=11, @z=12>
>>> b
> => []
>>>
>
> Here the results are not same as with the above. So is it calling my
> first instance method automatically? Couldn't understand the logic.


WHY do you think that? why you dont get the IDEA that it MAYBE calls 
to_ary? becaue *arg is the Splat Operator that parts Arrays into 
members, and MAYBE it calls to_ary is the object is not an Array?

-- 
Posted via http://www.ruby-forum.com/.