From: Love U Ruby <lists@...>
Date: 2013-02-16T19:40:57+09:00
Subject: Confusion with Ruby printing mechanics.

Here I just played to see how printing statement behaves with "nil"
values. Here we go:

>> p nil
nil
=> nil #good as expected.
>> puts nil
       #as nil.to_s causes the "blank" in the first line.
=> nil #good as expected.
>> p puts nil
    #as nil.to_s causes the "blank" in the first line
nil
=> nil # good as expected, as p works here on the return value of puts.

=========================

Confusion begins with the below :

>> p(puts(print("hi")))
hi
nil
=> nil # this is the actual output.

But from the above analysis I expected the below:

>> p(puts(print("hi")))
hi

nil
=> nil

Could you explain the gap between my assumption and the actual one?

Thanks.

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