From: Joel Pearson <lists@...>
Date: 2013-02-15T23:55:35+09:00
Subject: Re: Select "columns" from multidimensional array?

Hah, I wrote that head exploding comment first and then managed to work 
out what it did afterwards. Still took a few minutes of smashing my head 
into the desk to make room for the new thought though ;¬)

Using a Hash sounds like a good idea. I already tried rewriting the 
selector into something a bit more excel-like (although I won't bore you 
with all the little changes):

  def []( addr )
    col, row = addr.upcase.scan( /([A-Z]+)(\d+)/ ).flatten
    data[ index( row, col ) ]
  end

  def []=( addr, val )
    col, row = addr.upcase.scan( /([A-Z]+)(\d+)/ ).flatten
    data[ index( row, col ) ] = val
  end

m = Matrix.new(%w{A B C}, %w{1 2 3 4})
m["A1"] = 123
m["B4"] = 123

I haven't gotten around to changing all the "row, col" to "col, row" 
references, so it looks a bit weird, but I'm just experimenting with 
options at the moment. I'll have a go at Hashing it up as well.

Naturally I have many questions floating around in my head, but I'll try 
to work them out through the scientific method of repeated failed 
attempts :)

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