From: Stefano Crocco <stefano.crocco@...>
Date: 2013-02-03T06:00:06+09:00
Subject: Re: Why none of the block giving the expected output with the "enumerator"?

On Sunday 03 February 2013 Arup Rakshit wrote
> Stefano Crocco wrote in post #1094918:
> > On Sunday 03 February 2013 Arup Rakshit wrote
> > 
> >> => [11, 22, 31, 224, 44]
> >> 
> >>         from (irb):22:in `-'
> >>         from (irb):22:in `block in irb_binding'
> >>         from (irb):22:in `each'
> >>         from (irb):22:in `each'
> >>         from (irb):22
> >>         from C:/Ruby193/bin/irb:12:in `<main>'
> >> 
> >> irb(main):023:0>
> 
> @Stefano why is it calling Array's "each" method,instead of
> "enum#each",as i converted it to enumerator?
> 
> thanks
> 
> --
> Posted via http://www.ruby-forum.com/.

Because Enumerator#each, in turn, calls the each method of the object it was 
created from.

It is (more or less) if the enumerator was created this way:

class Enumerator

  def initialize object, method = :each
    @object = object
    @method = method
    @args = args
  end

  def each
    @object.send :method, *args
  end

end

Actually, Enumerator is written in C, so its implementation is different from 
this.

So, when you create an enumerator from an array, the #each method of the 
Enumerator calls the #each method of the array.

Stefano