From: Prasadhnc C <prasad.c82@...>
Date: 2013-01-30T15:03:50+09:00
Subject: Re: newbie question..

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u can try this,

string = 'hello'
string.split('').each.inject(Hash.new(0)) { |h, char| h[char] += 1; h }

Prasad C
On Wed, Jan 30, 2013 at 9:38 AM, Ryan Victory <ryan@raptormail.net> wrote:

> Out of curiosity, what did you do to get it working? I played around in
> irb after sending that (it was a quick guess, not anything I tried
> first) and ended up using two lines, both with
> Enumerable#each...couldn't get the hash to be used as the accumulator.
>
> -Ryan Victory
>
> On 1/29/13 8:55 PM, tamouse mailing lists wrote:
> > On Tue, Jan 29, 2013 at 8:45 PM, tamouse mailing lists
> > <tamouse.lists@gmail.com> wrote:
> >> On Tue, Jan 29, 2013 at 2:52 PM, Ryan Victory <ryan@raptormail.net>
> wrote:
> >>> For the same reason, I won't give you any answers, but your problem
> >>> could probably be solved using about two lines with the Array.inject
> >>> method and a Hash...think about it and ask questions. We are all here
> to
> >>> help, but we wouldn't want it to be too easy for you :-)
> >>
> >> Ok, I admit I'm stumped -- I don't get how to use a Hash inside an
> >> Array.inject -- I'm thinking it must be able to be done that way, but
> >> I just cannot grok it.
> >>
> >> #inject/#reduce/#fold are accumulators, but how does the Hash get
> >> passed from round to round?
> > Never mind, I got it...
> >
>
>
>

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<font><div>u can try this,</div><div>=A0</div><div>string =3D &#39;hello&#3=
9;</div><div>string.split(&#39;&#39;).each.inject(Hash.new(0)) { |h, char| =
h[char] +=3D 1; h }</div><div>=A0</div><div>Prasad C</div><div></div></font=
><div>
On Wed, Jan 30, 2013 at 9:38 AM, Ryan Victory <span dir=3D"ltr">&lt;<a href=
=3D"mailto:ryan@raptormail.net" target=3D"_blank">ryan@raptormail.net</a>&g=
t;</span> wrote:<br></div><div class=3D"gmail_quote"><blockquote style=3D"m=
argin:0px 0px 0px 0.8ex;padding-left:1ex;border-left-color:rgb(204,204,204)=
;border-left-width:1px;border-left-style:solid" class=3D"gmail_quote">
Out of curiosity, what did you do to get it working? I played around in<br>
irb after sending that (it was a quick guess, not anything I tried<br>
first) and ended up using two lines, both with<br>
Enumerable#each...couldn&#39;t get the hash to be used as the accumulator.<=
br>
<span class=3D"HOEnZb"><font color=3D"#888888"><br>
-Ryan Victory<br>
</font></span><div class=3D"HOEnZb"><div class=3D"h5"><br>
On 1/29/13 8:55 PM, tamouse mailing lists wrote:<br>
&gt; On Tue, Jan 29, 2013 at 8:45 PM, tamouse mailing lists<br>
&gt; &lt;<a href=3D"mailto:tamouse.lists@gmail.com">tamouse.lists@gmail.com=
</a>&gt; wrote:<br>
&gt;&gt; On Tue, Jan 29, 2013 at 2:52 PM, Ryan Victory &lt;<a href=3D"mailt=
o:ryan@raptormail.net">ryan@raptormail.net</a>&gt; wrote:<br>
&gt;&gt;&gt; For the same reason, I won&#39;t give you any answers, but you=
r problem<br>
&gt;&gt;&gt; could probably be solved using about two lines with the Array.=
inject<br>
&gt;&gt;&gt; method and a Hash...think about it and ask questions. We are a=
ll here to<br>
&gt;&gt;&gt; help, but we wouldn&#39;t want it to be too easy for you :-)<b=
r>
&gt;&gt;<br>
&gt;&gt; Ok, I admit I&#39;m stumped -- I don&#39;t get how to use a Hash i=
nside an<br>
&gt;&gt; Array.inject -- I&#39;m thinking it must be able to be done that w=
ay, but<br>
&gt;&gt; I just cannot grok it.<br>
&gt;&gt;<br>
&gt;&gt; #inject/#reduce/#fold are accumulators, but how does the Hash get<=
br>
&gt;&gt; passed from round to round?<br>
&gt; Never mind, I got it...<br>
&gt;<br>
<br>
<br>
</div></div></blockquote></div><br>

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