From: Ryan Victory <ryan@...>
Date: 2013-01-30T05:52:52+09:00
Subject: Re: newbie question..

For the same reason, I won't give you any answers, but your problem
could probably be solved using about two lines with the Array.inject
method and a Hash...think about it and ask questions. We are all here to
help, but we wouldn't want it to be too easy for you :-)

-Ryan Victory
On 1/29/13 2:50 PM, Wayne Brisette wrote:
> Since this is classwork, I won't give you the answer, but. Here's some things I 
> would do (and trust me there are *much* smarter people on this list), but I 
> would do probably use the case statement here. Seems to be a logical holding 
> point for things. 
>
> def sort_numbers(argv_input)
> case = argv_input
> when "1" one =+1
> etc... 
>
> end
>
> numbers = ARGV.split(" ")
>
> numbers.each do |num|
>
> sort_numbers(num)
>
> ### put your print routine here ###
>
> end
> Anyhow, that's how I would tackle it. But I'm sure there are better ways to code 
> this type of thing up. 
>
> Wayne
>
>
> ----- Original Message ----
> From: Zebulon Bowles <lists@ruby-forum.com>
> To: ruby-talk ML <ruby-talk@ruby-lang.org>
> Sent: Tue, January 29, 2013 2:41:28 PM
> Subject: newbie question..
>
> So I'm taking a class on Ruby and it seems as though the teacher has
> thrown something over my head.
>
>
> List how many times each number from 0 to 9 was mentioned.
> Example input:
>    > ruby most-common.rb 4 2 1 1 1 2
> Example output:
>    1 was mentioned 3 time(s).
>    2 was mentioned 2 time(s).
>    4 was mentioned 1 time(s).
> The numbers in the command-line arguments must always be between 0 and
> 9, inclusive.
>
> Do I loop over each element of an array of ARGV's and test to see if
> each new element of the array is equal to any of the others. And if so,
> do I set up a count?
>
> numbers = ARGV
>
>    for number in numbers
>         if number > 0 && < 9
>          ???????????????????
>
> end
>
> puts "#{number} was mentioned #{count} times?
>
> AHHHGH!!!!
>