From: "Derrick B." <lists@...>
Date: 2012-12-24T03:24:00+09:00
Subject: Re: simple division: -9 / 5 = -2 what?

7stud -- wrote in post #1089926:
> Derrick B. wrote in post #1089918:
>> $ irb
>> irb(main):001:0> -9 / 5
>> => -2
>> irb(main):002:0> -9.to_f / 5.to_f
>> => -1.8
>> irb(main):003:0> (-9.to_f / 5.to_f).to_i
>> => -1
>>
>> If I want to assign the integer quotient of the above example, do I
>> really need to go from float to integer?
>>
>
> No:
>
> p -9.divmod 5
>
> --output:--
> [-2, 1]

a = -9
b = 5
p a.divmod b )[0]
--output:--
-2

But I want a "correct" answer, which is not -2.  Hence:

p ( a.to_f / b.to_f ).to_i
--output:--
-1

...which is ugly, or better (maybe?):

p (a.fdiv b).to_i
--output:--
-1

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