From: botp <botpena@...>
Date: 2012-12-21T14:30:04+09:00
Subject: Re: Perl to Ruby: regex captures to assignment.

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On Fri, Dec 21, 2012 at 12:59 PM, Derrick B. <lists@ruby-forum.com wrote:
>....Lastly, my code I posted did not convert terms to improper
fractions,...

not to answer your questions, but, i'd probably go a different  route ...

eg,

require 'rational'
["1 3/4", "-2 1/2", "5/8", "-1/3", "5", "-5"].map do |mix|
  mix.split.map{|x| Rational(x)}
end

=> [ [(1/1), (3/4)],  [(-2/1), (1/2)],  [(5/8)],  [(-1/3)],  [(5/1)],
 [(-5/1)] ]

kind regards -botp

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<div dir=3D"ltr">On Fri, Dec 21, 2012 at 12:59 PM, Derrick B. <span dir=3D"=
ltr">&lt;<a href=3D"mailto:lists@ruby-forum.com" target=3D"_blank">lists@ru=
by-forum.com</a></span> wrote:<br><div>&gt;....Lastly, my code I posted did=
 not convert terms to improper fractions,...<br>
</div><div><br></div><div>not to answer your questions, but, i&#39;d probab=
ly go a different =C2=A0route ...=C2=A0<br><br>eg,<br></div><div><br></div>=
<div>require &#39;rational&#39;</div><div>[&quot;1 3/4&quot;, &quot;-2 1/2&=
quot;, &quot;5/8&quot;, &quot;-1/3&quot;, &quot;5&quot;, &quot;-5&quot;].ma=
p do |mix|<br>
=C2=A0 mix.split.map{|x| Rational(x)} =C2=A0<br>end =C2=A0<br></div><div><b=
r></div><div>=3D&gt; [ [(1/1), (3/4)],=C2=A0 [(-2/1), (1/2)],=C2=A0 [(5/8)]=
, =C2=A0[(-1/3)], =C2=A0[(5/1)], =C2=A0[(-5/1)] ]</div><div><br></div><div>=
kind regards -botp<br>=C2=A0<br></div><div>
<br></div></div>

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