From: Joao Silva <lists@...>
Date: 2012-07-09T05:13:08+09:00
Subject: Re: Find that number is repeated more and less times in an array

Brian Candler wrote in post #1067902:

> a = [1, 2, 2, 3, 5, 4, 6, 2, 6, 5, 4]
> counts = Hash.new(0)
> a.each { |val| counts[val] += 1 }
> groups = {}
> counts.each do |val,count|
>   groups[count] ||= []
>   groups[count] << val
> end
> groups.each do |count,vals|
>   puts "With #{count-1} repeats found #{vals.sort.join(", ")}"
> end
>

One last thing, how do I print the results that I stay in order, because
the above code prints:

With 0 repeats found 1, 3
With 2 repeats found 2
With 1 repeats found 4, 5, 6

and I seek it to print in order:

With 0 repeats found 1, 3
With 1 repeats found 4, 5, 6
With 2 repeats found 2

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