From: Joao Silva <lists@...>
Date: 2012-07-07T02:50:58+09:00
Subject: Re: Management of words in a string

"Jesús Gabriel y Galán" <jgabrielygalan@gmail.com> wrote in post
#1067632:

> You can use String#split method. You have to define very well what is
> a word for you. For example, consider things like "one-way street" or
> "it's raining", and also be careful with punctuation. A simplistic
> approach could be just to use the default split behaviour, which
> splits by the spaces:
>
> s = "this has words. how many? let's see"
> [5] pry(main)> s.split
> => ["this", "has", "words.", "how", "many?", "let's", "see"]
> [6] pry(main)> s.split.size
> => 7
>
> You can pass a regular expression to the split method to tune how you
> split.
>
> Jesus.

and in case you want to count the words that begin with a particular
letter (for example "a").

##############################################
ct=0

print "Enter a string: "
str=gets.chomp.to_s

puts "Word ==> #{str.split}"

if str.chr == "a"
  ct=ct+1
end

puts "Number of words that start with a: #{ct}"

#################################################

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