From: Jason Peterson <lists@...>
Date: 2012-07-07T01:44:11+09:00
Subject: Re: Parsing a zip file for rows of string data

Thank you for the reply. When I try running this I get a syntax error.

require 'zip/zip'

# To open the zip file and pass each entry to a block
Zip::ZipFile.foreach(C:\Data\file.zip) do |text_file|
   # Read from entry, turn String into Array, and pass to block
   text_file.read.split("\n").each do |line|
      if line.start_with?("CDI") || line.start_with?("CHO")

cdi_output = File.open("cdiout.txt", "a")  # Open an output file for CDI
cho_output = File.open("choout.txt", "a")  # Open an output file for CHO


  while line = f.gets                      # Read each line in the input
    cdi_output.puts line if /^CDI/ =~ line # Print if line starts with 
CDI
    cho_output.puts line if /^CHO/ =~ line # Print if line starts with 
CHO
  end
end

cdi_output.close                           # Close cdi_output file
cho_output.close                           # Close cho_output file

I appreciate any help

Thanks you, Jay

-- 
Posted via http://www.ruby-forum.com/.