From: Aleksey V Zapparov <ixti@...>
Date: 2012-07-04T17:57:00+09:00
Subject: Re: Newbie needs help with parsing a file

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On Wed, 4 Jul 2012 09:21:04 +0900
Ryan Davis <ryand-ruby@zenspider.com> wrote:

>=20
> On Jul 3, 2012, at 16:54 , Aleksey V Zapparov wrote:
>=20
> > On Wed, 4 Jul 2012 07:52:16 +0900
> > "Jon R." <lists@ruby-forum.com> wrote:
> >=20
> >> I have a file with a long string in the following format:
> >>=20
> >> /vol/dept115345K111455K/vol/home1156668K507768K...ad finitum.
> >>=20
> >> How do I iterate through the string comparing dividing the second
> >> number by the first number and only print the output if the number
> >> is 90% or more?  Basically the first number is total space and the
> >> second number is used space.  If the comparison is 90% or more,
> >> then print the vol name /vol/dept(etc.) along with the %.  If the
> >> comparison is less than 90% then don't print it at all.  In other
> >> words using the two above I would get
> >>=20
> >> /vol/dept 96.6%
> >=20
> >=20
> > str =3D "/vol/dept115345K111455K/vol/home1156668K507768K"
> >=20
> > str[1..-1].split("/").inject([]) do |arr, str|
> >  next arr if "vol" =3D=3D str
> >  next arr if 2 > arr.push(str).count
> >=20
> >  dept, home =3D arr
> >  puts "#{dept} VS #{home}"
> >=20
> >  []
> > end
>=20
> There are many tools in the String toolbox. #scan is often a much
> more powerful tool than #split:
>=20
> str =3D "/vol/dept115345K111455K/vol/home1156668K507768K"
>=20
> str.scan(%r%(/[a-z]+/[a-z]+)(\d+)K(\d+)K%).each do |(vol, quota,
> actual)| pct =3D actual.to_f / quota.to_f
>=20
>   next unless pct > 0.9
>=20
>   puts "%s %.1f%%" % [vol, pct * 100]
> end
>=20
>=20

Oh, man! You're absolutely right. I guess I need to avoid next time
writing to ML after 12 hours of work ;))


--=20
Sincerely yours,
Aleksey V. Zapparov A.K.A. ixti
FSF Member #7118
Mobile Phone: +34 677 990 688
Homepage: http://www.ixti.net
JID: zapparov@jabber.ru

*Origin: Happy Hacking!

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