From: Aleksey V Zapparov <ixti@...>
Date: 2012-07-02T01:22:38+09:00
Subject: Re: Question on Learning Ruby the Hard Way

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On Sun, 1 Jul 2012 21:19:53 +0900
Michael Sung <lists@ruby-forum.com> wrote:

> Hi, I have a question on Exercise 43 of Learning Ruby the Hard Way.
>=20
> Specifically, I'm wondering if someone to talk me through what's
> happening below.
>=20
> def play()
>     next_room =3D @start
>=20
>     while true
>       puts "\n--------"
>       room =3D method(next_room)
>       next_room =3D room.call()
>     end
>   end
>=20
>=20
> I can see that variable next_room is set to instance variable @start.
> But how does this "while" loop work?  I'm also not familiar with how
> "method" and "call" are both used here, as well as the : used in
> return (e.g. return :central_corridor) below.


Inside loop you are calling `method` instance method, which returns a
Method instance, in your case it's `central_corridor`, then you simply
calling it with `call()` same as `next_room =3D central_corridor()` at
least in the first time in that case. :))

See details here:
  - http://www.ruby-doc.org/core-1.9.3/Object.html#method-i-method
  - http://www.ruby-doc.org/core-1.9.3/Method.html


--=20
Sincerely yours,
Aleksey V. Zapparov A.K.A. ixti
FSF Member #7118
Mobile Phone: +34 677 990 688
Homepage: http://www.ixti.net
JID: zapparov@jabber.ru

*Origin: Happy Hacking!

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