From: Robert Klemme <shortcutter@...>
Date: 2012-06-26T18:31:23+09:00
Subject: Re: working with two arrays

On Tue, Jun 26, 2012 at 11:28 AM, Robert Klemme
<shortcutter@googlemail.com> wrote:
> On Tue, Jun 26, 2012 at 5:25 AM, Avdi Grimm <groups@inbox.avdi.org> wrote:
>> On Mon, Jun 25, 2012 at 9:06 PM, skolo pen <lists@ruby-forum.com> wrote:
>>>
>>> What method could I use to do the following:
>>>
>>> people = ["person1","person2","person3"]
>>>
>>> issue = ["issue1","issue2","issue3","issue4","issue5","issue6"]
>>>
>>> person1 => issue1
>>>
>>> person2 => issue2
>>>
>>> person3 => issue3
>>>
>>> person1 => issue4
>>>
>>> person2 => issue5
>>>
>>> person3 => issue6
>>>
>>
>> people.cycle.take(issue.size).zip(issue)
>
> We can do that shorter
>
> irb(main):004:0> issue.zip(people.cycle)
> => [["issue1", "person1"], ["issue2", "person2"], ["issue3",
> "person3"], ["issue4", "person1"], ["issue5", "person2"], ["issue6",
> "person3"]]

PS: if you want proper ordering, you can do

irb(main):005:0> issue.zip(people.cycle) {|i,p| printf "%s => %s\n", p, i}
person1 => issue1
person2 => issue2
person3 => issue3
person1 => issue4
person2 => issue5
person3 => issue6
irb(main):006:0> issue.zip(people.cycle).map {|i,p| [p,i]}
=> [["person1", "issue1"], ["person2", "issue2"], ["person3",
"issue3"], ["person1", "issue4"], ["person2", "issue5"], ["person3",
"issue6"]]

Kind regards

robert


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