From: Avdi Grimm <groups@...>
Date: 2012-06-26T12:25:23+09:00
Subject: Re: working with two arrays

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On Mon, Jun 25, 2012 at 9:06 PM, skolo pen <lists@ruby-forum.com> wrote:

> What method could I use to do the following:
>
> people = ["person1","person2","person3"]
>
> issue = ["issue1","issue2","issue3","issue4","issue5","issue6"]
>
> person1 => issue1
>
> person2 => issue2
>
> person3 => issue3
>
> person1 => issue4
>
> person2 => issue5
>
> person3 => issue6
>
>
people.cycle.take(issue.size).zip(issue)

Note that this will produce an array of arrays. A Hash doesn't work for
this because any given key can only appear once.

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On Mon, Jun 25, 2012 at 9:06 PM, skolo pen <span dir=3D"ltr">&lt;<a href=3D=
"mailto:lists@ruby-forum.com" target=3D"_blank">lists@ruby-forum.com</a>&gt=
;</span> wrote:<br><div class=3D"gmail_quote"><blockquote class=3D"gmail_qu=
ote" style=3D"margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex=
">

What method could I use to do the following:<br>
<br>
people =3D [&quot;person1&quot;,&quot;person2&quot;,&quot;person3&quot;]<br=
>
<br>
issue =3D [&quot;issue1&quot;,&quot;issue2&quot;,&quot;issue3&quot;,&quot;i=
ssue4&quot;,&quot;issue5&quot;,&quot;issue6&quot;]<br>
<br>
person1 =3D&gt; issue1<br>
<br>
person2 =3D&gt; issue2<br>
<br>
person3 =3D&gt; issue3<br>
<br>
person1 =3D&gt; issue4<br>
<br>
person2 =3D&gt; issue5<br>
<br>
person3 =3D&gt; issue6<br><font color=3D"#888888"><br></font></blockquote><=
div><br></div><div>people.cycle.take(issue.size).zip(issue)</div><div><br><=
/div><div>Note that this will produce an array of arrays. A Hash doesn&#39;=
t work for this because any given key can only appear once.=A0</div>

</div>

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