From: Emeka Patrick <lists@...>
Date: 2012-06-21T16:39:50+09:00
Subject: New to Ruby - Scope Question

x = 10
y = 5

def square(x)
  puts "within the method x is " + x.to_s
  puts x*x
end


In the above when defining the method, the x that is being referenced in
"x.to_s" and puts x*x is by default the variable x, defined above, with
a value of 10, correct?  This then means that even though this variable
isn't defined within the method it can still be called on from outside
the code. However, if the variable was given a value within the method
then it wouldn't be available outside of the method, correct?

Can someone explain why this is so. I guess I don't NEED to know why,
but I'd like to understand it a bit better if possible. Thanks!

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