From: "Jan E." <lists@...>
Date: 2012-06-14T18:39:09+09:00
Subject: Re: Simple method & array question

Hi,

Michael Sung wrote in post #1064551:
> For example, I tried:
>
> def repeat *arg
>   repeated = *arg
>   p repeated
> end

Why are you using *arg? This will take all the arguments of the method 
call (there may be any number) and put them into an array, which is 
referenced by arg.

For example:

#-------------------------
def f *args
  puts "args is #{args.inspect}"
end

f(1, 2, 3)  # args is [1, 2, 3]
f("a")      # args is ["a"]
f()         # args is []
#-------------------------

This is probably *not* what you want. You rather want the method to take 
a single argument (the array) and return this argument:

#-------------------------
def repeat array
  array
end
#-------------------------

Of course this method doesn't make sense (and it works not only for 
arrays but every object).

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