From: Robert Klemme <shortcutter@...>
Date: 2012-06-08T20:42:07+09:00
Subject: Re: Best way to partition a string

On Fri, Jun 8, 2012 at 12:20 PM, Iņaki Baz Castillo <ibc@aliax.net> wrote:
> 2012/6/8 Jan E. <lists@ruby-forum.com>:
>> "Iņaki Baz Castillo" <ibc@aliax.net> wrote in post #1063634:
>>> 2012/6/7 cyber c. <lists@ruby-forum.com>:
>>> Regexp.new(/^([a-zA-Z]+)(.+)$/).match(str).captures
>>
>> Why are you using Regexp.new, when /^([a-zA-Z]+)(.+)$/ already *is* a
>> Regexp? This seems nonsensical to me, like String.new("abc").
>
> Yes, I'm used to store my regexps in some module/class constants and
> usually use Regexp.new for some reason I don't remember right now,
> maybe because it allows passing a string which is useful in certain
> cases:
>
> Regexp.new("^([a-zA-Z]+)(.+)$")

Like

irb(main):001:0> s = "foo"
=> "foo"
irb(main):002:0> rx = /^([a-zA-Z]+)#{s}(.+)$/
=> /^([a-zA-Z]+)foo(.+)$/
irb(main):003:0> puts rx
(?-mix:^([a-zA-Z]+)foo(.+)$)
=> nil

?

Kind regards

robert

-- 
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