From: "Jan E." <lists@...>
Date: 2012-06-08T19:11:51+09:00
Subject: Re: Best way to partition a string

"Iñaki Baz Castillo" <ibc@aliax.net> wrote in post #1063634:
> 2012/6/7 cyber c. <lists@ruby-forum.com>:
> Regexp.new(/^([a-zA-Z]+)(.+)$/).match(str).captures

Why are you using Regexp.new, when /^([a-zA-Z]+)(.+)$/ already *is* a 
Regexp? This seems nonsensical to me, like String.new("abc").

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