From: ruby gem <lists@...>
Date: 2012-05-06T22:52:09+09:00
Subject: Re: proper way to create truly new dup/cloned object?

I think it is possible one of my gems is overriding the default behavior 
of dup, fast_xor:

puts @l
puts cloned_l

cipher = OpenSSL::Cipher::Cipher.new 'AES-256-CTR'
cipher.encrypt
cipher.key = cloned_l.xor!(subkey)
ciphertext = cipher.update(@r)
ciphertext << cipher.final
@r = ciphertext

puts @l
puts cloned_l

output:

8bll��h�43��u3;S�/�=�
                      @QM�W
8bll��h�43��u3;S�/�=�
                      @QM�W
톭qWOʁ/@�FI`�#����//��͟}��l
톭qWOʁ/@�FI`�#����//��͟}��l

is it possible for gem to over ride dup in this way? And if so how would 
you suggest going about this? my @l value changes over time , and 
fast_xor only does in place operations but in some instances I need to 
get l.xor! without the in place. I thought making a dup of it when I 
need its current value, but don't want to change the original string, 
would work. But it seems like it doesn't work because if it did it 
should output this

8bll��h�43��u3;S�/�=�
                      @QM�W
8bll��h�43��u3;S�/�=�
                      @QM�W
8bll��h�43��u3;S�/�=�
                      @QM�W
톭qWOʁ/@�FI`�#����//��͟}��l

can you think of an elegant way to do this? I don't want to have to keep 
adding and taking a bunch of things out of hashes but I am starting to 
think that is the only option.

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