From: Robert Klemme <shortcutter@...>
Date: 2012-04-26T17:11:23+09:00
Subject: Re: Method Missing as Filter

On Thu, Apr 26, 2012 at 1:46 AM, Hassan Schroeder
<hassan.schroeder@gmail.com> wrote:
> On Wed, Apr 25, 2012 at 4:13 PM, Christopher D. <lists@ruby-forum.com> wrote:
>
>> I can check that there is indeed a username ("Tom") and return 1 if
>> there is one and 0 by using this code
>> User.find_by_username("Tom")? 1 : 0
>>
>> How would I find out Tom's corresponding id?
>
> Here's a couple of ways:
>
>  @user = User.find_by_username("Tom") ? @user.id : 0
>
>  User.find_by_username("Tom").id rescue 0

Why waste a member variable for this?  I'd also stick with the truthy semantics:

def find_user_id_by_name(name)
  user = User.find_by_username(name) and user.id
end

> I'll bet there will be other suggestions :-)

You won.

Cheers

robert

-- 
remember.guy do |as, often| as.you_can - without end
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