From: "Bartosz Dziewoński" <matma.rex@...>
Date: 2012-04-17T02:16:18+09:00
Subject: Re: Operator overloading of the subscript operator

W dniu 16 kwietnia 2012 07:02 użytkownik Eric Christopherson
<echristopherson@gmail.com> napisał:
> Oh, I see. Still, Ruby doesn't seem to convert foo`bar` into
> foo.`(bar) the way it converts foo[bar] into foo.[](bar):
>
> class Foo
>  def `(x)
>    puts "backticks around #{x}"
>  end
> end
>
> f = Foo.new
> f`bar`

Well, yes.

f`bar` is the same as f(`bar`).

`bar` is the same as self.`("bar"). You can't change the self here.

-- Matma Rex