From: Intransition <transfire@...>
Date: 2012-01-22T10:54:07+09:00
Subject: Re: [regexp] How to convert string "/regexp/i" to /regexp/i - ?

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Something like:
   
   key = "ixm"

   x = str.reverse_index('/')

   v = str[x+1..-1]

   o = v.characters.inject(0){ |s,c| b = key.index(c); b ? 2**b : 0 }

   Regexp.new(str[1...x], o)

Or

  eval "%r#{str}"

If safety is a concern you can get Pretty Good(tm) safety by wrapping it in 
a threaded $SAFE=4. Too bad Ruby doesn't support %R, then it would 
perfectly safe.



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Something like:<br>&nbsp;&nbsp; <br>&nbsp;&nbsp; key = "ixm"<br><br>&nbsp;&nbsp; x = str.reverse_index('/')<br><br>&nbsp;&nbsp; v = str[x+1..-1]<br><br>&nbsp;&nbsp; o = v.characters.inject(0){ |s,c| b = key.index(c); b ? 2**b : 0 }<br><br>&nbsp;&nbsp; Regexp.new(str[1...x], o)<br><br>Or<br><br>&nbsp; eval "%r#{str}"<br><br>If safety is a concern you can get Pretty Good(tm) safety by wrapping it in a threaded $SAFE=4. Too bad Ruby doesn't support %R, then it would perfectly safe.<br><br><br>
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