From: Gary Wright <gwtmp01@...>
Date: 2011-12-31T14:55:16+09:00
Subject: Re: output file from variable


On Dec 30, 2011, at 8:31 PM, Alex Sweps wrote:
> Thank you very much for the reply but for your solution to work i would 
> need the file name of the original file being read. I am inputing my 
> file via ARGV[0] so i cannot specify the original filename. Seeing as 
> the variable x contains the entire file is there a way i can output x 
> into a new file and name the file with a variable?
> I simply want a way to rename the input file :(

ARGV[0] *is* the name of the original file so:

   File.rename(ARGV[0], new_filename)

should work.


Gary Wright